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Value
PostPosted: 12 Apr 2023, 02:24 
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Joined: 23 Jan 2021, 01:58
Posts: 6
As the question, how to get the value of Footer under the group within the group.
My version is trial version 11.0
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EhLibSupport
PostPosted: 12 Apr 2023, 17:04 
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Joined: 08 May 2014, 18:06
Posts: 663
Do you mean when the DBGridEh.DataGrouping.Active = True?


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Value
PostPosted: 15 Apr 2023, 01:57 
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Joined: 23 Jan 2021, 01:58
Posts: 6
EhLibSupport wrote:
Do you mean when the DBGridEh.DataGrouping.Active = True?


Yes, how do I get it please?
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EhLibSupport
PostPosted: 17 Apr 2023, 13:51 
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Joined: 08 May 2014, 18:06
Posts: 663
Hello

The value of the footer depends on which grouping row you are on in the grid.
If you want to get the footer value for the current grouping row for the PartPrice column, you can use the following code:

Code:
procedure TfrDataGrouping.Button1Click(Sender: TObject);
var
  ColIndex: Integer;
  FooterVal: Variant;
  GroupNodeRow: TGroupDataTreeNodeEh;
begin
  GroupNodeRow := DBGridEh1.DataGrouping.CurDataNode;
  if (GroupNodeRow.NodeType <> dntDataGroupEh) then
  begin
    ShowMessage('Current row is not group caption');
    Exit;
  end;

  ColIndex := DBGridEh1.FieldColumns['PartPrice'].Index;
  FooterVal := GroupNodeRow.FooterItems[0].FooterValues[ColIndex];
  ShowMessage(VarToStr(FooterVal));
end;

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Value
PostPosted: 18 Apr 2023, 05:41 
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Joined: 23 Jan 2021, 01:58
Posts: 6
EhLibSupport wrote:
Hello

The value of the footer depends on which grouping row you are on in the grid.
If you want to get the footer value for the current grouping row for the PartPrice column, you can use the following code:

Code:
procedure TfrDataGrouping.Button1Click(Sender: TObject);
var
  ColIndex: Integer;
  FooterVal: Variant;
  GroupNodeRow: TGroupDataTreeNodeEh;
begin
  GroupNodeRow := DBGridEh1.DataGrouping.CurDataNode;
  if (GroupNodeRow.NodeType <> dntDataGroupEh) then
  begin
    ShowMessage('Current row is not group caption');
    Exit;
  end;

  ColIndex := DBGridEh1.FieldColumns['PartPrice'].Index;
  FooterVal := GroupNodeRow.FooterItems[0].FooterValues[ColIndex];
  ShowMessage(VarToStr(FooterVal));
end;



Thank you very much, it solved my problem
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